300=8y^2-192y

Solution for 300=8y^2-192y equation:

300=8y^2-192y

We move all terms to the left:

300-(8y^2-192y)=0

We get rid of parentheses

-8y^2+192y+300=0

a = -8; b = 192; c = +300;
Δ = b2-4ac
Δ = 1922-4·(-8)·300
Δ = 46464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{46464}=\sqrt{7744*6}=\sqrt{7744}*\sqrt{6}=88\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-88\sqrt{6}}{2*-8}=\frac{-192-88\sqrt{6}}{-16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+88\sqrt{6}}{2*-8}=\frac{-192+88\sqrt{6}}{-16}
$